Calculate the concentration of chromate ion (CrO42-) in a 0.450 M solution of chromic acid (H2CrO4) .[For chromic acid, Ka1 = 0.18, Ka2 = 3.2 × 10-7.]
A) 3.2 × 10-7 M
B) 1.5 × 10-6 M
C) 0.081 M
D) 1.1 × 10-6 M
E) 0.21 M
Correct Answer:
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