What mass of water would need to evaporate from your skin in order to dissipate 1.7 * 10⁵ J of heat from your body? H₂O(l)$\rarr$H₂O(g)$\Delta$H_vap = 40.7 kJ/mol A)7.52 * 10⁴ g B)418 g C)75.2 g D)58.4 g E)6.92 * 10⁶ g

Question

Quizplus · Accepted Answer

First, we need to use the formula q = mΔHvap to find the mass of water that needs to evaporate:

q = mΔHvap
1.7 × 10^10 J = m × 40.7 kJ/mol
m = (1.7 × 10^10 J) / (40.7 kJ/mol) = 4.177 × 10^5 mol

Next, we need to convert moles to grams using the molar mass of water:

m = 4.177 × 10^5 mol × 18.015 g/mol = 7.52 × 10^6 g = 75.2 g

Therefore, the answer is C: 75.2 g.

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