In the gas phase, formic acid forms a dimmer, 2HCOOH(g) (HCOOH)₂(g). For this reaction, $\Delta$H° = -60.1 kJ/mol and $\Delta$G° = -13.9 kJ/mol at 25°C. Find the equilibrium constant (K_p)for this reaction at 75 °C. A)8960 B)273 C)0.120 D)8.33 E)1.12 $\times$ 10^-4

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The Answer of In the gas phase, formic acid forms a dimmer, 2HCOOH(g) (HCOOH)₂(g). For this reaction, $\Delta$H° = -60.1 kJ/mol and $\Delta$G° = -13.9 kJ/mol at 25°C. Find the equilibrium constant (K_p)for this reaction at 75 °C. A)8960 B)273 C)0.120 D)8.33 E)1.12 $\times$ 10^-4

In the Gas Phase, Formic Acid Forms a Dimmer, 2HCOOH(g) Δ\DeltaΔ

In the Gas Phase, Formic Acid Forms a Dimmer, 2HCOOH(g) $\Delta$