Red colored Kool-Aid crystals are added to a still glass of hot water. The same amount of crystals are added to a second still glass filled with the same amount of cold water. With no stirring, which of the following would occur?
A)Without stirring, both glasses will reach uniform color in the same amount of time since they both contain identical amounts of water.
B)The glass of cold water will reach a uniform red color first since there are no heat convection currents to impede the distribution of the dye.
C)The glass of hot water will reach a uniform red color first since the higher kinetic energy provides for faster moving molecules to more quickly distribute the dye.
D)The Kool-aid crystals will never dissolve in either glass until the glasses are stirred.

Question

Quizplus · Accepted Answer

The higher kinetic energy of the hot water molecules will allow for faster movement and distribution of the dye, leading to a faster uniform color in the glass of hot water.

Red Colored Kool-Aid Crystals Are Added to a Still Glass