How many moles of water, O, are produced from the reaction of 16 grams methane, C , with an unlimited supply of oxygen, . How many grams of O is this? C + 2 → C + 2 O
A)0.889 mole, which is 16 grams
B)2.0 moles of water, which is 32 grams
C)2.0 moles of water, which is 36 grams
D)1.0 mole of water, which is 18 grams

Question

How many moles of water,  O, are produced from the reaction of 16 grams methane, C  , with an unlimited supply of oxygen,  . How many grams of  O is this? C  + 2  → C  + 2  O
A)0.889 mole, which is 16 grams 
B)2.0 moles of water, which is 32 grams 
C)2.0 moles of water, which is 36 grams 
D)1.0 mole of water, which is 18 grams

Quizplus · Accepted Answer

The balanced equation shows that for every 1 mole of methane, 2 moles of water are produced. 
First, we need to convert the given mass of methane to moles:
16 g / (16.04 g/mol) = 0.998 mol
Since there is an unlimited supply of oxygen, we assume that all the methane is completely consumed in the reaction. Therefore, we can use the mole ratio from the balanced equation to find the amount of water produced:
0.998 mol CH4 x (2 mol H2O / 1 mol CH4) = 1.996 mol H2O
Finally, we can convert the moles of water to grams:
1.996 mol H2O x (18.02 g/mol) = 35.99 g or approximately 36 g of water, which is choice C.

How Many Moles of Water, O, Are Produced from the Reaction