What is the concentration (M)of CH₃OH in a solution prepared by dissolving 11.7 g of CH₃OH in sufficient water to give exactly 230. mL of solution? A)11.9 B)1.59 C)0.00159 D)3.17 E)0.0841

Question

Quizplus · Accepted Answer

First, we need to calculate the number of moles of CH3OH in the solution:

moles = mass/molar mass
moles = 11.7 g / 32.04 g/mol
moles = 0.365 mol

Next, we need to convert the volume of the solution from mL to L:

volume = 230 mL / 1000 mL/L
volume = 0.23 L

Finally, we can calculate the concentration (Molarity) of the solution:

Molarity = moles/volume
Molarity = 0.365 mol / 0.23 L
Molarity = 1.59 M

Therefore, the concentration of CH3OH in the solution is 1.59 M. The answer is B.

What Is the Concentration (M)of CH3OH in a Solution Prepared

What Is the Concentration (M)of CH₃OH in a Solution Prepared