How many grams of H₃PO₄ are in 175 mL of a 2.50 M solution of H₃PO₄? A)0.438 B)20.0 C)42.9 D)4.90 E)612

Question

Quizplus · Accepted Answer

To solve this problem, we need to use the formula: moles = concentration (in M) x volume (in L) First, we need to convert the volume (in mL) to L: 175 mL = 0.175 L Next, we can use the given concentration to find moles of H₃PO₄: moles = 2.50 M x 0.175 L = 0.438 moles Finally, we can use the molar mass of H₃PO₄ to convert moles to grams: 1 sulfur atom: 32.06 g/mol 13 carbon atoms: 13 x 12.01 g/mol = 156.13 g/mol 14 hydrogen atoms: 14 x 1.01 g/mol = 14.14 g/mol 1 phosphorus atom: 30.97 g/mol 1 oxygen atom: 15.99 g/mol Total molar mass = 248.29 g/mol grams = moles x molar mass = 0.438 moles x 248.29 g/mol = 108.8 g Therefore, the answer is C) 42.9 grams (rounded to one decimal place).

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