An 8.29 g sample of calcium carbonate [CaCO₃ (s)] absorbs 50.3 J of heat, upon which the temperature of the sample increases from 21.1 °C to 28.5 °C. What is the specific heat of calcium carbonate?

Question

Quizplus · Accepted Answer

The specific heat (c) can be calculated using the formula q = mcΔT, where q is the heat absorbed (50.3 J), m is the mass (8.29 g), and ΔT is the change in temperature (28.5 °C - 21.1 °C = 7.4 °C). Solving for c gives c = q / (mΔT) = 50.3 J / (8.29 g * 7.4 °C) ≈ 0.82 J/g°C.

An 829 G Sample of Calcium Carbonate [CaCO3 (S)] Absorbs 50

An 829 G Sample of Calcium Carbonate [CaCO₃ (S)] Absorbs 50