The temperature of a 35.2 g sample of iron increases from 23.7 °C to 29.5 °C. If the specific heat of iron is 0.450 J/g-K, how many joules of heat are absorbed?

Question

Quizplus · Accepted Answer

First, calculate the change in temperature:

ΔT = T2 - T1 = 29.5 °C - 23.7 °C = 5.8 °C

Then, use the specific heat formula:

q = m * c * ΔT

where q is the heat absorbed, m is the mass of the sample, c is the specific heat, and ΔT is the change in temperature.

Plugging in the values:

q = 35.2 g * 0.450 J/g-K * 5.8 °C

q = 92.016 J

Rounding to three significant figures, the answer is 92 J. Therefore, the best choice is B, 92.

The Temperature of a 35