Find ΔH for BaCO3 (s) → BaO (s) + CO2 (g) given 2 Ba (s) + O2 (g) → 2 BaO (s) ΔH = -1107.0 kJ
Ba (s) + CO2 (g) + 1/2 O2 (g) → BaCO3 (s) ΔH = -822.5 kJ
A) -1929.5 kJ
B) +1376 kJ
C) -269.0 kJ
D) 269.0 kJ
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