The reaction that occurs in a Breathalyzer,a device used to determine the alcohol level in a person's bloodstream,is given below.If the rate of appearance of Cr₂(SO₄)₃ is 1.24 mol/min at a particular moment,what is the rate of disappearance of C₂H₆O at that moment? 2 K₂Cr₂O₇ + 8 H₂SO₄ + 3 C₂H₆O → 2 Cr₂(SO₄)₃ + 2 K₂SO₄ + 11 H₂O

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The stoichiometry of the reaction shows that 3 moles of $C_2H_5OH$ react to produce 2 moles of $Cr_2(SO_4)_3$. Therefore, if $Cr_2(SO_4)_3$ is appearing at a rate of 1.24 mol/min, the rate of disappearance of $C_2H_5OH$ can be calculated using the ratio of their stoichiometric coefficients (3:2). Thus, for every 2 moles of $Cr_2(SO_4)_3$ formed, 3 moles of $C_2H_5OH$ are consumed. The rate of disappearance of $C_2H_5OH$ is $1.24 \times \frac{3}{2} = 1.86$ mol/min.

The Reaction That Occurs in a Breathalyzer,a Device Used to Determine