The first-order reaction,SO₂Cl₂ → SO₂ + Cl₂,has a rate constant equal to 2.20 × 10^-5 s^-1 at 593 K.What percentage of the initial amount SO₂Cl₂ will remain after 3.00 hours?

Question

Quizplus · Accepted Answer

For a first-order reaction, the percentage remaining can be calculated using the formula: % remaining = 100 * e^(-kt). Substituting k = 2.20 × 10^-5 s^-1 and t = 3 hours (or 10800 seconds), we find that approximately 78.9% of SO2Cl2 remains.

The First-Order Reaction,SO2Cl2 → SO2 + Cl2,has a Rate Constant

The First-Order Reaction,SO₂Cl₂ → SO₂ + Cl₂,has a Rate Constant