The Second-Order Reaction 2 Mn(CO)₅ → Mn₂(CO)₁₀,has a Rate Constant

The second-order reaction 2 Mn(CO) ₅ → Mn₂(CO) ₁₀,has a rate constant equal to 3.0 × 10⁹ M^-1 s^-1 at 25°C.If the initial concentration of Mn(CO) ₅ is 5.0 × 10^-5 M,how long will it take for 90.% of the reactant to disappear?

A) 1.7 × 10^-15 s
B) 1.9 × 10^-14 s
C) 6.0 × 10^-5 s
D) 1.5 × 10² s