Nitric oxide reacts with oxygen to form nitrogen dioxide: 2 NO(g) + O₂(g) ⇌ 2 NO₂(g)
What is K_c'for the reverse reaction if the equilibrium concentration of NO is 0.300 M,O₂ is 0.200 M,and NO₂ is 0.530 M at 25°C?

Question

Quizplus · Accepted Answer

The equilibrium constant expression for the given reaction is: Kc = [NO₂]^2 / ([NO]^2 * [O₂]) Substituting the given equilibrium concentrations: Kc = (0.530 M)^2 / ((0.300 M)^2 * (0.200 M)) = 0.0641 Since the given equilibrium is for the forward reaction, the equilibrium constant for the reverse reaction is the reciprocal of Kc: Kc' = 1/Kc = 1/0.0641 = 15.6 Therefore, the answer is B.

Nitric Oxide Reacts with Oxygen to Form Nitrogen Dioxide: 2