Given the reaction: 2 HI ⇌ H₂ + I₂.If K_c^' for the reverse reaction is 1.85 × 10^-2 at 425°C,what is K_c for the forward reaction at the same temperature?

Question

Quizplus · Accepted Answer

The equilibrium constant for the forward reaction ($K_c$) is the reciprocal of the equilibrium constant for the reverse reaction. Given $K_c$ for the reverse reaction is $1.85 \times 10^{-2}$, for the forward reaction it is $1 / (1.85 \times 10^{-2}) = 54.1$.

Given the Reaction: 2 HI ⇌ H2 + I2

Given the Reaction: 2 HI ⇌ H₂ + I₂