An equilibrium mixture of CO,O₂ and CO₂ at a certain temperature contains 0.0010 M CO₂ and 0.0015 M O₂.At this temperature,K_c,equals 1.4 × 10² for the reaction: 2 CO(g) + O₂(g) ⇌ 2 CO₂(g) .
What is the equilibrium concentration of CO?

Question

Quizplus · Accepted Answer

The equilibrium constant $K_c$ for the reaction $2 CO(g) + O_2(g) \rightleftharpoons 2 CO_2(g)$ is given by $K_c = \frac{[CO_2]^2}{[CO]^2[O_2]}$. Given $K_c = 1.4 \times 10^{12}$, $[CO_2] = 0.0010$ M, and $[O_2] = 0.0015$ M, we can solve for $[CO]$. Rearranging the equation for $K_c$, we get $[CO] = \sqrt{\frac{[CO_2]^2}{K_c[O_2]}}$. Plugging in the given values, $[CO] = \sqrt{\frac{(0.0010)^2}{1.4 \times 10^{12} \times 0.0015}} = 2.2 \times 10^{-3}$ M.

An Equilibrium Mixture of CO,O2 and CO2 at a Certain

An Equilibrium Mixture of CO,O₂ and CO₂ at a Certain