At 25°C,a certain first order reaction has a rate constant equal to 1.00 × 10^-3 s^-1 and an equilibrium constant,K_c,equal to 4.18.What is the rate constant for the reverse reaction?

Question

Quizplus · Accepted Answer

The equilibrium constant for a reaction can be related to the rate constants of the forward and reverse reactions using the following equation:

K = kf/kr

Where K is the equilibrium constant, kf is the rate constant for the forward reaction, and kr is the rate constant for the reverse reaction.

Rearranging this equation, we get:

kr = kf/K

Substituting the given values, we get:

kr = (1.00 × 10^-13 s^-1) / 4.18

kr = 2.39 × 10^-14 s^-1

Therefore, the answer is choice A: 2.39 × 10^-14 s^-1.

At 25°C,a Certain First Order Reaction Has a Rate Constant