Consider the following standard reduction potentials, Zn²⁺(aq)+ 2 e^- → Zn(s)E° = -0.76 V I₂(s)+ 2 e^- → 2 I^-(aq)E° = +0.54 V Under standard conditions, A)Zn²⁺(aq)is a stronger oxidizing agent than I₂(s)and I^-(aq)is a stronger reducing agent than Zn(s). B)I₂(s)is a stronger oxidizing agent than Zn²⁺(aq)and Zn(s)is a stronger reducing agent than I^-(aq). C)Zn(s)is a stronger oxidizing agent than I^-(aq)and Zn²⁺(aq)is a stronger reducing agent than I₂(s). D)I^-(aq)is a stronger oxidizing agent than Zn(s)and I₂(s)is a stronger reducing agent than Zn²⁺(aq).

Question

Quizplus · Accepted Answer

The standard reduction potential of I₂(s) is higher than Zn²⁺(aq), indicating that I₂(s) is a stronger oxidizing agent than Zn²⁺(aq). Similarly, the standard reduction potential of Zn(s) is higher than that of I^-(aq), indicating that Zn(s) is a stronger reducing agent than I^-(aq). Therefore, option B is the correct choice.

Consider the Following Standard Reduction Potentials, Zn2+(aq)+ 2 E- →

Consider the Following Standard Reduction Potentials, Zn²⁺(aq)+ 2 E^- →