What is the standard cell potential for the reaction below? Pb(s) + Br₂(l) → Pb²⁺(aq) + 2 Br^-(aq)
The standard reduction potential is -0.13 V for the Pb²⁺/Pb half-cell and +1.09 V for the Br₂/Br^- half-cell.

Question

Quizplus · Accepted Answer

The standard cell potential ($E^\circ_{cell}$) is calculated by subtracting the standard reduction potential of the anode ($E^\circ_{anode}$) from the standard reduction potential of the cathode ($E^\circ_{cathode}$). Here, $E^\circ_{cathode} = +1.09 V$ for Br2/Br- and $E^\circ_{anode} = -0.13 V$ for Pb2+/Pb. Thus, $E^\circ_{cell} = +1.09 V - (-0.13 V) = +1.22 V$.

What Is the Standard Cell Potential for the Reaction Below