The active ingredient in many antacid tablets is calcium carbonate,CaCO₃.How many moles of calcium carbonate are contained in a tablet weighing 550.mg?

Question

Quizplus · Accepted Answer

To calculate the number of moles of calcium carbonate (CaCO3) present in the tablet, we need to use the formula:

moles = mass / molar mass

The molar mass of CaCO3 can be calculated by adding the atomic masses of its constituent atoms:

molar mass of CaCO3 = atomic mass of Ca + atomic mass of C + 3 x atomic mass of O
molar mass of CaCO3 = 40.08 g/mol + 12.01 g/mol + 3 x 16.00 g/mol
molar mass of CaCO3 = 100.09 g/mol

Now we can substitute the given values into the formula:

moles = 0.550 g / 100.09 g/mol
moles = 0.00551 mol

Therefore, there are 0.00551 moles of CaCO3 in the tablet, or 5.51 x 10^-3 moles, which is closest to option C.

The Active Ingredient in Many Antacid Tablets Is Calcium Carbonate,CaCO3

The Active Ingredient in Many Antacid Tablets Is Calcium Carbonate,CaCO₃