Which is the limiting reactant when 3.00 g of calcium are reacted with 8.00 g of water to produce hydrogen gas in the following equation?
Ca(s) + 2 H₂O(l) → Ca(OH) ₂(aq) + H₂(g)

Question

Which is the limiting reactant when 3.00 g of calcium are reacted with 8.00 g of water to produce hydrogen gas in the following equation? Ca(s)+ 2 H₂O(l)→ Ca(OH)₂(aq)+ H₂(g)

Quizplus · Accepted Answer

Calculate the moles of each reactant: 
moles Ca = 3.00 g / 40.08 g/mol = 0.0748 mol 
moles H2O = 8.00 g / 18.02 g/mol = 0.444 mol

According to the balanced equation, 1 mol of Ca reacts with 2 mol of H2O. Therefore, the maximum amount of Ca that can react is 0.0748 mol * (2/1) = 0.1496 mol. This means that H2O is in excess and Ca is the limiting reactant.

Which Is the Limiting Reactant When 3