A solution containing 145.0 g AgNO₃ is mixed with a CaCl₂ solution and 98.4 of AgCl is recovered.Calculate the % yield of the reaction.

Question

Quizplus · Accepted Answer

The theoretical yield of AgCl can be calculated using stoichiometry. The molar mass of AgNO3 is 169.87 g/mol, so 145.0 g corresponds to 0.853 moles. The reaction AgNO3 + CaCl2 → AgCl + Ca(NO3)2 shows a 1:1 molar ratio, so 0.853 moles of AgCl is expected. The molar mass of AgCl is 143.32 g/mol, so the theoretical yield is 122.2 g. The % yield is (98.4 g / 122.2 g) * 100% = 80.44%.

A Solution Containing 145