What absorbed dose of protons with an RBE of 17 will cause the same damage to biological tissue as a 200 rd dose of neutrons that have an RBE of 2.6?
A)3.8 rd
B)12 rd
C)26 rd
D)52 rd
E)520 rd

Question

Quizplus · Accepted Answer

First, we need to calculate the equivalent dose of the neutron radiation:

Equivalent dose = absorbed dose x RBE 
Equivalent dose = 200 rd x 2.6 
Equivalent dose = 520 rd

Now we can use the equivalent dose and RBE of the proton radiation to find the absorbed dose that would cause the same biological damage:

Equivalent dose = absorbed dose x RBE 
520 rd = absorbed dose x 17 
absorbed dose = 520 rd / 17 
absorbed dose ≈ 30.6 rd

Therefore, the absorbed dose of protons with an RBE of 17 that would cause the same biological damage as a 200 rd dose of neutrons with an RBE of 2.6 is approximately 30.6 rd. However, since none of the answer choices match this value exactly, we need to choose the closest option. The closest option is B) 12 rd, which is reasonable since it is roughly halfway between 3.8 rd and 26 rd.

What Absorbed Dose of Protons with an RBE of 17