A coil consists of 240 circular loops, each of radius 0.044 m, and carries a current of 2.2 A. Determine the magnetic moment of the coil.

Question

Quizplus · Accepted Answer

The magnetic moment (m) of a coil is given by the formula:

m = nIA

where n is the number of turns, I is the current, and A is the cross-sectional area of the coil.

We are given that:

n = 240 (number of circular loops)
I = 2.2 A (current)
r = 0.044 m (radius)
A = πr^2 = 3.14*(0.044)^2 = 0.00607 m^2 (cross-sectional area)

Substituting these values into the formula, we get:

m = nIA
m = 240 * 2.2 * 0.00607
m = 3.21 A m^2

Therefore, the magnetic moment of the coil is 3.2 A ⋅ m^2, which corresponds to option C.

A Coil Consists of 240 Circular Loops, Each of Radius