A solenoid of length 0.250 m and radius 0.0250 m is comprised of 440 turns of wire. Determine the magnitude of the magnetic field at the center of the solenoid when it carries a current of 12.0 A.

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Quizplus · Accepted Answer

The magnetic field at the center of a solenoid is given by:$$B = \mu_0 n I$$where:* B is the magnetic field in teslas (T)* μ0 is the permeability of free space (4π × 10^-7 T·m/A)* n is the number of turns per unit length (in this case, 440 turns / 0.250 m = 1760 turns/m)* I is the current in amperes (A)Plugging in the given values, we get:$$B = (4π × 10^-7 T·m/A) × (1760 turns/m) × (12.0 A) = 2.21 × 10^-3 T$$Therefore, the magnitude of the magnetic field at the center of the solenoid is 2.21 × 10^-3 T.

A Solenoid of Length 0