The plates of a parallel plate capacitor each have an area of 0.40 m 2 and are separated by a distance of 0.02 m. They are charged until the potential difference between the plates is 3000 V. The charged capacitor is then isolated.
-Determine the magnitude of the electric field between the capacitor plates.

Question

Quizplus · Accepted Answer

The magnitude of the electric field between the capacitor plates is given by E = V/d, where V is the potential difference between the plates and d is the distance between them.

Substituting the given values, we get:

E = 3000 V / 0.02 m 
E = 1.5 × 10^5 V/m

Therefore, the correct answer is D) 1.5 × 10^5 V/m.

The Plates of a Parallel Plate Capacitor Each Have an Area