The plates of a parallel plate capacitor each have an area of 0.40 m 2 and are separated by a distance of 0.02 m. They are charged until the potential difference between the plates is 3000 V. The charged capacitor is then isolated.
-Determine the value of the capacitance.

Question

Quizplus · Accepted Answer

The capacitance of a parallel plate capacitor is given by:

C = εA/d

Where ε is the permittivity of free space (8.85 x 10^-12 F/m), A is the area of each plate, and d is the distance between the plates.

Plugging in the given values:

C = (8.85 x 10^-12 F/m) x 0.40 m^2 / 0.02 m

C = 1.8 x 10^-10 F

Therefore, the value of the capacitance is 1.8 × 10^-10 F or 1.8 × 10^-8 μF, which is option B.

The Plates of a Parallel Plate Capacitor Each Have an Area