A circular loop of wire with a diameter of 0.626 m is rotated in a uniform electric field to a position where the electric flux through the loop is a maximum. At this position, the electric flux is 7.50 × 10⁵ N.m²/C. Determine the magnitude of the electric field.

Question

Quizplus · Accepted Answer

The electric flux through a circular loop of radius r in a uniform electric field E is given by:

Φ = πr²E

Since the diameter of the loop is given as 0.626 m, the radius is 0.313 m.

At the position where the electric flux is a maximum, the loop is perpendicular to the electric field. Therefore, we can equate the given electric flux to the above equation to find the magnitude of the electric field:

7.50 × 10⁻¹⁵ C/N = π(0.313 m)²E
E = (7.50 × 10⁻¹⁵ C/N) / π(0.313 m)²
E = 2.44 × 10¹⁶ N/C

Therefore, the answer is (C).

A Circular Loop of Wire with a Diameter of 0