A 2.0-kg object is attached to a spring (k = 55.6 N/m) that hangs vertically from the ceiling. The object is displaced 0.045 m vertically. When the object is released, the system undergoes simple harmonic motion. What is the magnitude of the maximum acceleration of the object? A)1.3 m/s² B)2.3 m/s² C)4.4 m/s² D)9.8 m/s² E)11 m/s²

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Quizplus · Accepted Answer

The maximum acceleration of the object is given by a = (k/m) * A, where k is the spring constant, m is the mass of the object, and A is the amplitude of the motion. Plugging in the given values, we get a = (55.6 N/m) * (0.045 m) / (2.0 kg) = 1.3 m/s^2.

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