Write the equilibrium constant for 2NaBr(aq) + Pb(ClO4) 2(aq) ![Write the equilibrium constant for 2NaBr(aq) + Pb(ClO<sub>4</sub>) <sub>2</sub>(aq) PbBr<sub>2</sub>(s) + 2NaClO<sub>4</sub>(aq) . A) K = [Pb<sup>2+</sup>][Br <sup>-</sup> ]<sup>2 </sup> B) K = 1/([Pb<sup>2+</sup>][Br<sup>-</sup>]<sup>2</sup>) C) K = [NaClO<sub>4</sub>]<sup>2</sup>/([NaBr]<sup>2</sup>[Pb(ClO<sub>4</sub>) <sub>2</sub>] D) K = [PbBr<sub>2</sub>]/([Pb<sup>2+</sup>][Br<sup>-</sup>]<sup>2</sup>) E) K = 1/([Pb(ClO<sub>4</sub>) <sub>2</sub>][NaBr]<sup>2</sup>)](https://d2lvgg3v3hfg70.cloudfront.net/TB1039/11ea7e73_3883_508b_9a0a_fbd8e9b2367d_TB1039_11.jpg)
PbBr2(s) + 2NaClO4(aq) .
A) K = [Pb2+][Br - ]2
B) K = 1/([Pb2+][Br-]2)
C) K = [NaClO4]2/([NaBr]2[Pb(ClO4) 2]
D) K = [PbBr2]/([Pb2+][Br-]2)
E) K = 1/([Pb(ClO4) 2][NaBr]2)
Correct Answer:
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