Consider the reaction 2CuBr₂(s)$\rightarrow$2CuBr(s)+ Br₂(g)If the equilibrium vapor pressure of Br₂(g) Is 1.43 * 10 ^- ⁵ Torr at 298 K,What is $\Delta$G at this temperature when Br₂(g) Is produced at a pressure of 7.50 * 10 ^- ⁷ Torr?

Question

Quizplus · Accepted Answer

The change in Gibbs free energy ($\Delta G$) can be calculated using the equation $\Delta G = \Delta G^\circ + RT \ln(Q)$, where $Q$ is the reaction quotient. Given the equilibrium vapor pressure and the pressure at which Br$_2$ is produced, $\Delta G$ can be calculated, resulting in -7.31 kJ.

Consider the Reaction 2CuBr2(s) →\rightarrow→ 2CuBr(s)+ Br2(g)If the Equilibrium Vapor Pressure of Br2(g) Is 1

Consider the Reaction
2CuBr₂(s) $\rightarrow$ 2CuBr(s)+ Br₂(g)If the Equilibrium Vapor Pressure of Br₂(g)
Is 1