Consider the reaction NO(g)+$\frac { 1 } { 2 }$O₂(g)$\rightarrow$NO₂(g) If$\Delta$H^$\omicron$ = - 56.52 kJ and $\Delta$S^$\omicron$ = - 72.60 J . K ^- ¹ at 298 K, What is the equilibrium constant for the reaction at 298 K?

Question

Quizplus · Accepted Answer

The equilibrium constant (K) can be calculated using the Gibbs free energy change ($\Delta G^\omicron$) and the relation $\Delta G^\omicron = -RT \ln K$. First, calculate $\Delta G^\omicron$ using $\Delta G^\omicron = \Delta H^\omicron - T\Delta S^\omicron$. Then solve for K. Given the values, the correct choice is A.

Consider the Reaction NO(g) 12\frac { 1 } { 2 }21​

Consider the Reaction
NO(g) $\frac { 1 } { 2 }$