The amino acid alanine,HOOC-CH(CH₃)NH₃⁺,Has K_a1 = 4.5 * 10^-³ and K_a2 = 1.4 * 10^-¹⁰.Calculate$\alpha$(^-OOC-CH(CH₃)NH₃⁺)At pH 10.

Question

Quizplus · Accepted Answer

The correct answer is A because at pH 10, the concentration of H+ ions is 10^-10 M. This means that the amino acid is mostly in the form of its conjugate base, -OOC-CH(CH3)NH3+, and the value of α(-OOC-CH(CH3)NH3+) is 0.42.

The Amino Acid Alanine,HOOC-CH(CH3)NH3+,Has Ka1 = 4 α\alphaα (-OOC-CH(CH3)NH3+)At PH 10

The Amino Acid Alanine,HOOC-CH(CH₃)NH₃⁺,Has K_a1 = 4 $\alpha$ (^-OOC-CH(CH₃)NH₃⁺)At PH 10