How many moles of O₂(g) are produced by electrolysis of Na₂SO₄(aq)
If 0.120 A is passed through the solution for 65.0 min?

Question

How many moles of O₂(g) are produced by electrolysis of Na₂SO₄(aq) If 0.120 A is passed through the solution for 65.0 min?

Quizplus · Accepted Answer

The correct answer is A because the number of moles of O2(g) produced by electrolysis of Na2SO4(aq) can be calculated using Faraday's law of electrolysis. The amount of charge passed through the solution is Q = It = (0.120 A)(65.0 min)(60 s/min) = 468 C. The number of moles of electrons transferred is n = Q/F = (468 C)/(96,485 C/mol) = 0.00485 mol. Since each mole of O2(g) requires 4 moles of electrons, the number of moles of O2(g) produced is 0.00485 mol / 4 = 0.00121 mol.

How Many Moles of O2(g) Are Produced by Electrolysis of Na2SO4(aq)

How Many Moles of O₂(g) Are Produced by Electrolysis of Na₂SO₄(aq)