How many moles of magnesium oxide are produced by the reaction of 1.82 g of magnesium nitride with of water?
Mg₃N₂ + 3H₂O → 2NH₃ + 3MgO

Question

How many moles of magnesium oxide are produced by the reaction of 1.82 g of magnesium nitride with of water? Mg₃N₂ + 3H₂O → 2NH₃ + 3MgO A)0.0180 B)0.0541 C)0.00601 D)0.984 E)3.00

Quizplus · Accepted Answer

First, we need to calculate the number of moles of magnesium nitride using its molar mass:

1.82 g Mg3N2 x (1 mol Mg3N2 / 100.95 g Mg3N2) = 0.018 mol Mg3N2

Next, we can use stoichiometry to determine the number of moles of magnesium oxide produced. From the balanced equation, we see that 3 moles of MgO are produced for every 1 mole of Mg3N2 reacted:

0.018 mol Mg3N2 x (3 mol MgO / 1 mol Mg3N2) = 0.054 mol MgO

Therefore, the answer is B) 0.0541 moles of magnesium oxide.

How Many Moles of Magnesium Oxide Are Produced by the Reaction