Sulfur and fluorine react in a combination reaction to produce sulfur hexafluoride: S (s) + 3F₂(g) → SF₆ (g)
The maximum amount of SF₆ that can be produced from the reaction of 32.1 g of sulfur with of fluorine is ________ g.

Question

Sulfur and fluorine react in a combination reaction to produce sulfur hexafluoride: S (s) + 3F₂(g) → SF₆ (g)
The maximum amount of SF₆ that can be produced from the reaction of 32.1 g of sulfur with

Sulfur and fluorine react in a combination reaction to produce sulfur hexafluoride: S (s) + 3F<sub>2</sub>(g) → SF<sub>6</sub> (g) The maximum amount of SF<sub>6</sub> that can be produced from the reaction of 32.1 g of sulfur with of fluorine is ________ g. A) 584 B) 438 C) 146 D) 48.7 E) 219

of fluorine is ________ g.

Quizplus · Accepted Answer

First, we need to determine which reactant is limiting, meaning which reactant will be fully consumed first and thus limit the amount of product that can be formed. This can be done using stoichiometry and comparing the amount of product that would be formed from each reactant.

For sulfur: 
32.1 g S x (1 mol S / 32.06 g S) x (1 mol SF6 / 1 mol S) x (SF6 molar mass / 1 mol SF6) = 154.8 g SF6

For fluorine: 
11.07 g F2 x (1 mol F2 / 38.00 g F2) x (1 mol SF6 / 3 mol F2) x (SF6 molar mass / 1 mol SF6) = 48.7 g SF6

Since fluorine produces a lower amount of SF6, it is the limiting reactant. Therefore, the maximum amount of SF6 that can be produced is 48.7 g. So the correct answer is D.

Sulfur and Fluorine React in a Combination Reaction to Produce