Lithium and nitrogen react to produce lithium nitride: 6Li (s) + N₂ (g) → 2Li₃N (s)
How many moles of N₂are needed to react with 0.550 mol of lithium?

Question

Lithium and nitrogen react to produce lithium nitride: 6Li (s)+ N₂ (g)→ 2Li₃N (s) How many moles of N₂are needed to react with 0.550 mol of lithium? A)3.30 B)0.550 C)0.183 D)1.65 E)0.0917

Quizplus · Accepted Answer

According to the balanced equation, 6 moles of Li react with 1 mole of N₂. Therefore, 0.550 moles of Li will react with 0.550/6 = 0.0917 moles of N₂.

Lithium and Nitrogen React to Produce Lithium Nitride: 6Li (S)