Consider the following two reactions: A → 2B ΔH°_rxn= 456.7 kJ/mol A → C ΔH°_rxn= -22.1 kJ/mol Determine the enthalpy change for the process: 2B → C A)-478.8 kJ/mol B)-434.6 kJ/mol C)434.6 kJ/mol D)478.8 kJ/mol E)More information is needed to solve the problem.

Question

Quizplus · Accepted Answer

We can use Hess's Law to solve the problem. By summing up the two given reactions, we get:
2B - A = -456.7 kJ/mol 
C - A = 22.1 kJ/mol
Multiplying the first equation by -1 and adding the two equations, we obtain:
2B - C = -478.8 kJ/mol, which is the enthalpy change for the process 2B → C. Therefore, the answer is A, -478.8 kJ/mol.

Consider the Following Two Reactions: a → 2B ΔH°rxn =

Consider the Following Two Reactions: a → 2B ΔH°_rxn=