A mixture of He and Ne at a total pressure of 0.95 atm is found to contain 0.32 mol of He and 0.56 mol of Ne.The partial pressure of Ne is ________ atm.
A)1.7
B)1.5
C)0.60
D)0.35
E)1.0

Question

Quizplus · Accepted Answer

The partial pressure of a gas in a mixture can be calculated using the formula: $P_{\text{gas}} = X_{\text{gas}} \times P_{\text{total}}$, where $X_{\text{gas}}$ is the mole fraction of the gas. The mole fraction of Ne is calculated as $\frac{0.56}{0.32 + 0.56} = \frac{0.56}{0.88}$. The partial pressure of Ne is then $0.636 \times 0.95 \approx 0.60$ atm.

A Mixture of He and Ne at a Total Pressure