If 3.21 mol of a gas occupies 56.2 L at 44 °C and 793 torr,4.73 mol of this gas occupies ________ L under these conditions.
A)14.7
B)61.7
C)30.9
D)82.8
E)478

Question

Quizplus · Accepted Answer

Using the ideal gas law, $PV = nRT$, where $P$ is pressure, $V$ is volume, $n$ is the number of moles, $R$ is the ideal gas constant, and $T$ is temperature. Since the conditions (temperature and pressure) are the same for both amounts of gas, the volume is directly proportional to the number of moles. Therefore, we can use the ratio $\frac{3.21 \, \text{mol}}{56.2 \, \text{L}} = \frac{4.73 \, \text{mol}}{x \, \text{L}}$. Solving for $x$ gives $x = \frac{4.73 \, \text{mol} \times 56.2 \, \text{L}}{3.21 \, \text{mol}} = 82.8 \, \text{L}$.

If 321 Mol of a Gas Occupies 56