The volume of 1.26 mol of gas at 69.4 kPa and 25.30 °C is ________ L.
A)45.1
B)633
C)3.82
D)0.445
E)0.439

Question

Quizplus · Accepted Answer

Using the ideal gas law, $PV = nRT$, where $P$ is the pressure in kPa, $V$ is the volume in liters, $n$ is the number of moles, $R$ is the ideal gas constant (8.314 L·kPa/(mol·K)), and $T$ is the temperature in Kelvin. Convert 25.30°C to Kelvin: 25.30 + 273.15 = 298.45 K. Solve for $V$: $V = \frac{nRT}{P} = \frac{1.26 \times 8.314 \times 298.45}{69.4}$ ≈ 45.1 L.

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