The rate of disappearance of HBr in the gas phase reaction 2HBr (g) → H₂ (g) + Br₂ (g)
Is 0.140 M at 150 °C.The rate of reaction is ________ M .

Question

The rate of disappearance of HBr in the gas phase reaction 2HBr (g)→ H₂ (g)+ Br₂ (g) Is 0.140 M at 150 °C.The rate of reaction is ________ M .

Quizplus · Accepted Answer

The rate of the reaction is proportional to the rate of disappearance of HBr. Therefore, the rate of the reaction is also 0.140 M. However, the question is asking for the rate of reaction in units of M/s. To find this, we need to divide the rate of the reaction by the stoichiometric coefficient of HBr, which is 2. This gives us:

Rate of reaction = 0.140 M / 2 = 0.0700 M/s

Therefore, the answer is B.

The Rate of Disappearance of HBr in the Gas Phase