A compound decomposes by a first-order process.If 13% of the compound decomposes in 60 minutes,the half-life of the compound is ________ min.

Question

Quizplus · Accepted Answer

For a first-order process, the half-life (t_1/2) is related to the rate constant (k) by the equation t_1/2 = 0.693/k. The rate constant can be found using the first-order kinetics equation: ln([A]_0/[A]) = kt, where [A]_0 is the initial concentration, [A] is the concentration at time t, and k is the rate constant. Given that 13% decomposes in 60 minutes, 87% remains. Substituting the given values into the equation: ln(1/0.87) = k*60. Solving for k and then calculating t_1/2 gives a value close to 299 minutes.

A Compound Decomposes by a First-Order Process