The solubility of manganese (II)hydroxide (Mn(OH)₂)is What is the K_sp of Mn(OH)₂? A)1.1 × 10^-14 B)4.3 × 10^-14 C)2.1 × 10^-14 D)4.8 × 10^-10 E)2.2 × 10^-5

Question

Quizplus · Accepted Answer

The solubility product constant (Ksp) expression for manganese (II) hydroxide can be written as:

Mn(OH)2(s) ⇌ Mn2+(aq) + 2OH-(aq)

Ksp = [Mn2+][OH-]2

Since the solubility of Mn(OH)2 is given as 11.0 × 10-7 mol/L, we can use stoichiometry to find the concentrations of Mn2+ and OH- ions produced when Mn(OH)2 dissolves in water.

Let x be the molar solubility of Mn(OH)2. Then, according to the balanced chemical equation, [Mn2+] = x and [OH-] = 2x.

Substituting these values into the Ksp expression, we get:

Ksp = (x)(2x)2 = 4x3

Since Ksp is given as 1.1 × 10-13, we can solve for x:

4x3 = 1.1 × 10-13

x = (1.1 × 10-13/4)1/3 = 4.31 × 10-5 mol/L

Therefore, the Ksp of Mn(OH)2 is:

Ksp = (4.31 × 10-5)(2(4.31 × 10-5))2 = 4.3 × 10-14

The closest answer choice is B, which is 4.3 × 10-14.

The Solubility of Manganese (II)hydroxide (Mn(OH)2)is What Is the Ksp

The Solubility of Manganese (II)hydroxide (Mn(OH)₂)is What Is the K_sp