For a given reaction with ΔH = -28.1 kJ/mol,the ΔG = 0 at The value of ΔS must be assuming that ΔH and ΔS do not vary with temperature.

Name: For a given reaction with ΔH = -28.1 kJ/mol,the ΔG = 0 at The value of ΔS must be assuming that ΔH and ΔS do not vary with temperature.
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Question

For a given reaction with ΔH = -28.1 kJ/mol,the ΔG = 0 at  The value of ΔS must be  assuming that ΔH and ΔS do not vary with temperature.

Quizplus · Accepted Answer

ΔG = ΔH - TΔS

When ΔG = 0,

0 = -28.1 kJ/mol - (T)(ΔS)

ΔS = 28.1 kJ/mol ÷ T

Assuming the temperature is 298 K,

ΔS = 28.1 kJ/mol ÷ (298 K) = -75.5 J/(mol∙K)

So the answer is choice A.

For a Given Reaction with ΔH = -28