For a body emitting blackbody radiation,the total power emitted is proportional to the 4th power of the body's absolute temperature: (T in kelvins)
and the wavelength of the emitted EM radiation that has the highest intensity is inversely proportional to the body's absolute temperature according to: ( in meters,T in kelvins)
Assume an object is emitting blackbody radiation.
-If the Kelvin temperature of an object is doubled,the amount of radiant energy emitted each second is twice the original amount.

Question

For a body emitting blackbody radiation,the total power emitted is proportional to the 4th power of the body's absolute temperature:  (T in kelvins)
and the wavelength of the emitted EM radiation that has the highest intensity is inversely proportional to the body's absolute temperature according to:  (  in meters,T in kelvins)
Assume an object is emitting blackbody radiation.
-If the Kelvin temperature of an object is doubled,the amount of radiant energy emitted each second is twice the original amount.

Quizplus · Accepted Answer

The radiant energy emitted by an object is proportional to the fourth power of its temperature (Stefan-Boltzmann Law), so doubling the Kelvin temperature increases the energy by a factor of 2^4, or 16 times.

For a Body Emitting Blackbody Radiation,the Total Power Emitted Is