For a body emitting blackbody radiation,the total power emitted is proportional to the 4th power of the body's absolute temperature: (T in kelvins)
and the wavelength of the emitted EM radiation that has the highest intensity is inversely proportional to the body's absolute temperature according to: ( in meters,T in kelvins)
Assume an object is emitting blackbody radiation.
-The peak of a body's blackbody radiation curve shifts upward as the temperature of the body increases.

Question

For a body emitting blackbody radiation,the total power emitted is proportional to the 4th power of the body's absolute temperature:  (T in kelvins)
and the wavelength of the emitted EM radiation that has the highest intensity is inversely proportional to the body's absolute temperature according to:  (  in meters,T in kelvins)
Assume an object is emitting blackbody radiation.
-The peak of a body's blackbody radiation curve shifts upward as the temperature of the body increases.

Quizplus · Accepted Answer

According to the second law mentioned in the prompt, as the temperature of the body increases, the wavelength of the emitted radiation that has the highest intensity decreases. This shift towards shorter wavelengths is also known as blue-shifting. Hence, the peak of the body's blackbody radiation curve shifts upward as the temperature increases. Therefore, the statement is true.

For a Body Emitting Blackbody Radiation,the Total Power Emitted Is