For a body emitting blackbody radiation,the total power emitted is proportional to the 4th power of the body's absolute temperature: (T in kelvins)
and the wavelength of the emitted EM radiation that has the highest intensity is inversely proportional to the body's absolute temperature according to: ( in meters,T in kelvins)
Assume an object is emitting blackbody radiation.
-The peak of a body's blackbody radiation curve shifts toward longer wavelength as the temperature of the body increases.

Question

For a body emitting blackbody radiation,the total power emitted is proportional to the 4th power of the body's absolute temperature:  (T in kelvins)
and the wavelength of the emitted EM radiation that has the highest intensity is inversely proportional to the body's absolute temperature according to:  (  in meters,T in kelvins)
Assume an object is emitting blackbody radiation.
-The peak of a body's blackbody radiation curve shifts toward longer wavelength as the temperature of the body increases.

Quizplus · Accepted Answer

The peak of a body's blackbody radiation curve actually shifts towards shorter wavelengths as the temperature of the body increases (known as Wien's displacement law).

For a Body Emitting Blackbody Radiation,the Total Power Emitted Is