For a body emitting blackbody radiation,the total power emitted is proportional to the 4th power of the body's absolute temperature: (T in kelvins)
and the wavelength of the emitted EM radiation that has the highest intensity is inversely proportional to the body's absolute temperature according to: ( in meters,T in kelvins)
Assume an object is emitting blackbody radiation.
-A body in a room at 300 K is heated to 3,000 K.The amount of energy radiated each second by the body increases 10,000 times.

Question

For a body emitting blackbody radiation,the total power emitted is proportional to the 4th power of the body's absolute temperature:  (T in kelvins)
and the wavelength of the emitted EM radiation that has the highest intensity is inversely proportional to the body's absolute temperature according to:  (  in meters,T in kelvins)
Assume an object is emitting blackbody radiation.
-A body in a room at 300 K is heated to 3,000 K.The amount of energy radiated each second by the body increases 10,000 times.

Quizplus · Accepted Answer

The total power emitted by the body is proportional to the 4th power of its absolute temperature. Therefore, increasing the temperature from 300 K to 3,000 K will result in an increase in the amount of energy radiated each second by a factor of (3,000/300)^4 = 10^4. This means that the statement is true.

For a Body Emitting Blackbody Radiation,the Total Power Emitted Is