Minimization of $\sum _ { i = 1 } ^ { n } \left( Y _ { i } - b _ { 0 } - b _ { 1 } X _ { 1 i } - \ldots - b _ { k } X _ { k i } \right) ^ { 2 }$ results in A) $X ^ { \prime }$ Y = X $\hat \beta$ B)X $\hat \beta$ = 0_k₊₁. C) $X ^ { \prime }$ (Y - X $\hat \beta$ )= 0_k₊₁. D)R? = r.

Question

Quizplus · Accepted Answer

The Answer is C

Minimization Of ∑i=1n(Yi−b0−b1X1i−…−bkXki)2\sum _ { i = 1 } ^ { n } \left( Y _ { i } - b _ { 0 } - b _ { 1 } X _ { 1 i } - \ldots - b _ { k } X _ { k i } \right) ^ { 2 }∑i=1n​(Yi​−b0​−b1​X1i​−…−bk​Xki​)2

Minimization Of $\sum _ { i = 1 } ^ { n } \left( Y _ { i } - b _ { 0 } - b _ { 1 } X _ { 1 i } - \ldots - b _ { k } X _ { k i } \right) ^ { 2 }$